Найти корни уравнения: [tex] x^{2} - 4 + 5 x^{3} - 20x = 0[/tex]. Created by l89123951754. algebra-ru

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August 2022 1 2 Report

Найти корни уравнения: [tex] x^{2} - 4 + 5 x^{3} - 20x = 0[/tex]

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sangers1959

Verified answer

X²-4+5x³-20x=0
5x³+x²-20x-4=0
x₁=2
5x³+x²-20x-4 I_x-2_
5x³-10x² I 5x²+11x+2
______
11x²-20x
11x²-22x
------------
2x-4
2x-4
-------
0
5x²+11x+2=0 D=81
x₂=-2 x₃=-0,2
Ответ: x₁=2 x₂=-2 x₃=-0,2.

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Answers & Comments

Verified answer

skolko mozhet byt reshenij u sistemy dvuh linejnyj uravnenij s dvumya peremennymi

razlozhit mnogochlen 2m3nk2mk3nk2m3n na mnozhiteli

715 23 pomogite pozhalujsta

chem pechenochniki otlichayutsya ot listostebelnyh mhov kratko19d3b5f7bba687fac5b2fb53f0d97f3d 90477

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