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yahoo223
@yahoo223
July 2022
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[tex] \frac{ 125^{x}- 5^{x} }{25 ^{x} } [/tex]
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sangers1959
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(125^x-5^x)/25^x=((5³)^x-5^x)/(5²)^x=(5^(3x)-5^x)/5^(2x)=
=5^x(5^(2x)-1)/5^(2x)=(5^(2x)-1)/5^x=5^x-1/5^x=5^x-5^(-x).
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(125^x-5^x)/25^x=((5³)^x-5^x)/(5²)^x=(5^(3x)-5^x)/5^(2x)==5^x(5^(2x)-1)/5^(2x)=(5^(2x)-1)/5^x=5^x-1/5^x=5^x-5^(-x).