tex]...

pubger3003 @pubger3003

July 2022 1 3 Report

[tex]{4}^{x} - {2}^{x + 1} = 80[/tex]

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NNNLLL54

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$4^{x}-2^{x+1}=80\\\\\star \; \; 4^{x}=(2^2)^{x}=2^{2x}=(2^{x})^2\; \; \star \\\\(2^{x})^2-2^{x}\cdot 2^1-80=0\\\\t=2^{x}>0\; \; \to \; \; \; t^2-2t-80=0\; ,\; \; t_1=-8\; ,\; t_2=10\; \; (teorema\; Vieta)\\\\t_1=-8$

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