Home
О нас
Products
Services
Регистрация
Войти
Поиск
youonelove
@youonelove
July 2022
1
9
Report
Производная. Помогите, пожалуйста.
1. ((2х-3)(3х+1))'
2. [tex]( \frac{x}{ \sqrt{x} +1} + \frac{x}{ \sqrt{x} -1} )'[/tex]
3. [tex] (\frac{3 \sqrt{x} }{2+ \sqrt{x} } )'[/tex]
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
Verified answer
1
2*(3x+1)+3*(2x-3)=6x+2+6x-9=12x-7
2
[1(√x+1)-x*1/√x]/(√x+1)²+[1*(√x-1)-x*1/2√x]/(√x-1)²=
=(√x+1-√x)/(√x+1)²+(√x-1-√x)/(√x-1)²=1/(√x+1)²-1/(√x-1)²=
(x-2√x+1-x-2√x-1)/(x-1)²=-4√x/(x-1)²
3
[3/2√x*(2+√x)-3√x*1/2√x]/(2+√x)²=(6+3√x-3√x)/[2√x(2+√x)²]=3/[√x(2+√x)²]
0 votes
Thanks 1
More Questions From This User
See All
youonelove
August 2022 | 0 Ответы
pomogite reshit pozhalujsta x2 1 xx 2
Answer
youonelove
August 2022 | 0 Ответы
pomogite pozhalujsta 1 zapishite dve kakie libo okrestnosti chisla 5 dvumya spos
Answer
youonelove
August 2022 | 0 Ответы
pomogite pozhalujsta88edfeb975ec943c23f972bda91c2e7f 11771
Answer
youonelove
August 2022 | 0 Ответы
pomogite reshit pozhalujsta1035a3174bdf051dc8f4180ca6b753c0 50129
Answer
youonelove
August 2022 | 0 Ответы
dano ad1 kub kaa1 ebb1 nc1d1 postroit sechenie ken s postroeniem po
Answer
youonelove
August 2022 | 0 Ответы
srochnotyazhyolyj sunduk peremeshayut podkladyvaya pod nego katki odinakovye kuski
Answer
youonelove
August 2022 | 0 Ответы
pomogite pozhalujsta chemu ravna emkost v mkf kondensatora esli pri uvelichen
Answer
youonelove
August 2022 | 0 Ответы
kmolk4f8e93087b5d2c1566ccfcefcc054747 13016
Answer
youonelove
August 2022 | 0 Ответы
4...
Answer
youonelove
August 2022 | 0 Ответы
tex metod neopredelennyh koefficientov
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "tex]..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
12*(3x+1)+3*(2x-3)=6x+2+6x-9=12x-7
2
[1(√x+1)-x*1/√x]/(√x+1)²+[1*(√x-1)-x*1/2√x]/(√x-1)²=
=(√x+1-√x)/(√x+1)²+(√x-1-√x)/(√x-1)²=1/(√x+1)²-1/(√x-1)²=
(x-2√x+1-x-2√x-1)/(x-1)²=-4√x/(x-1)²
3
[3/2√x*(2+√x)-3√x*1/2√x]/(2+√x)²=(6+3√x-3√x)/[2√x(2+√x)²]=3/[√x(2+√x)²]