tex]...

August 2022 1 13 Report

Найти предел функции, не пользуясь правилом Лопиталя

[tex] \lim_{x \to 6} \frac{x^2 -9x+18}{3 x^{2} -17x+6} [/tex]

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SRT1905 $\lim_{x \to 6} \frac{x^2 -9x+18}{3 x^{2} -17x+6} = \lim_{x \to 6} \frac{6^2 -9*6+18}{3 *6^{2} -17*6+6} =lim_{x \to 6} \frac{36 -54+18}{108-102+6} =$
$=lim_{x \to 6} \frac{0}{12} =0$

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