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cos([tex] \frac{ \pi }{2} +x)=1[/tex]
[tex]log_{5} (5-x)= log_{5} 3[/tex]
[tex] \sqrt{2} cosx-1=0[/tex]
cos([tex] \frac{ \pi }{2} +x)=1[/tex]
[tex]log_{5} (5-x)= log_{5} 3[/tex]
[tex] \sqrt{2} cosx-1=0[/tex]
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π/2+x = 2πn, n∈Z
x = -π/2 + 2πn, n∈Z
2. одз: 5-x>0; x<5
5-x=3 => x=2
3. cos(x) = sqrt(2)/2
x=+-π/4 + 2πn, n∈Z