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mary222
@mary222
August 2022
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[tex]Log_{4}x-log_{12}x=log_{12}27[/tex]
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ranaexotic
Log4x-Log12x=log12^27 перейдем к новому основанию1.(1/logx4)-(1/logx12)=log12^27 2)logx12/logx4=log12^27. 3) logx8=log12^274) 3logx2=3log12^3 5). Logx2=log12^3 6). Log12^3= 1728.7) logx2-logx^1728=0 8) logx^(2/1728)=0. 9) logx^1/864=0 . 10) x=1/864
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