[tex]\frac{4}{b-5} + \frac{1}{b} \\ \frac{4}{b-5} + \frac{1}{b} \\ \frac{3}{a+b} - \frac{5}{a-b} [/tex]. Created by Buhich. algebra-ru

tex]...

July 2022 1 5 Report

[tex]\frac{4}{b-5} + \frac{1}{b} \\ \frac{4}{b-5} + \frac{1}{b} \\ \frac{3}{a+b} - \frac{5}{a-b}

[/tex]

Answers & Comments

Сюръекция $\frac{4b+b-5}{b(b-5)} = \frac{5b-5}{b^{2}-5b}$
$\frac{3(a-b)-5(a+b)}{(a-b)(a+b)}= \frac{3a-3b-5a-5b}{a^{2}-b^{2}}= \frac{-2a-8b}{a^{2}-b^{2}}$

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