x⁴=(2x-3)²
x²=I2x-3I
1) x²=I2x-3I
a) x≥1,5
x²-2x+3=0
D= 4-12= -8
D<0, корней нет
б) x<1,5
x²+2x-3=0
D= 4+12= 16
x1= (-2+4)/2= 1
x2= (-2-4)/2= -3
Ответ: x1= 1, x2= -3
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Verified answer
x⁴=(2x-3)²
x²=I2x-3I
1) x²=I2x-3I
a) x≥1,5
x²-2x+3=0
D= 4-12= -8
D<0, корней нет
б) x<1,5
x²+2x-3=0
D= 4+12= 16
x1= (-2+4)/2= 1
x2= (-2-4)/2= -3
Ответ: x1= 1, x2= -3