[tex] \sqrt{-2x+3} =x[/tex]. Created by Catolker. algebra-ru

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ОДЗ
x ≥ 0

- 2x + 3 = x^2
x^2 + 2x - 3 = 0
D= 4 + 12 = 16
x1 = ( - 2 + 4)/2 = 1
x2 = ( - 2 - 4)/2 = - 3 не удовлетворяет ОДЗ

Ответ
1

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233334 $\left \{ {{x \geq 0,} \atop {-2x+3=x^2;}} \right. \left \{ {{x \geq 0,} \atop { x^2+2x-3=0;} }} \right. \left \{ {{x \geq 0,} \atop {x_{1}=-3, x_{2}=1; }} \right.$
Ответ:1.

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