[tex] \sqrt{-2x+3} =x[/tex]. Created by Catolker. algebra-ru

ОДЗx ≥ 0- 2x + 3 = x^2x^2 + 2x - 3 = 0 D= 4 + 12 = 16x1 = ( - 2 + 4)/2 = 1x2 = ( - 2 - 4)/2 = - 3 не удовлетворяет ОДЗОтвет1