Найдите значение выражения [tex] \frac{( \sqrt{6} + \sqrt{14} ) ^{2} }{10+ \sqrt{84} } [/tex]. Created by romanoffarsenij. algebra-ru

tex]...

MizoriesKun $\frac{( \sqrt{6}+ \sqrt{14}) ^{2} }{10+ \sqrt{84} }= \frac{( \sqrt{6}) ^{2}+2 \sqrt{84}+( \sqrt{14} ) ^{2} }{10+ \sqrt{84} } = \frac{6+2 \sqrt{84}+14 }{10+ \sqrt{84} }= \frac{20+2 \sqrt{84} }{10+ \sqrt{84} }= \frac{2(10+ \sqrt{84)} }{10+ \sqrt{84} }=$ $2$

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Verified answer

(√6+ √14)² 6+2√84+14 2(10+√84)
------------------- = --------------------- = --------------------- = 2
10+√84 10+√84 10+√84

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