tex])...

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Избавиться от иррациональности в знаменателе:

1/(1+[tex]\sqrt[3]{2}[/tex]+[tex]\sqrt[3]{4}[/tex])

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Artem112

Verified answer

$\dfrac{1}{1+\sqrt[3]{2}+\sqrt[3]{4}}=\dfrac{1-\sqrt[3]{2}}{(1-\sqrt[3]{2})( 1+\sqrt[3]{2}+(\sqrt[3]{2})^2)}=\dfrac{1-\sqrt[3]{2}}{1^3-(\sqrt[3]{2})^3}=\\\\=\dfrac{1-\sqrt[3]{2}}{1-2}=\dfrac{1-\sqrt[3]{2}}{-1}=\sqrt[3]{2}-1$

2 votes Thanks 1

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Answers & Comments

Verified answer

v ryadu soedinenij alcl3 gt hbr gt nh3 0gt co2 gt mgi2 gtgt zns ch

(a*2); if frac(a)=0 then writeln(t,a) else begin a:= int(a); a:=a + 1; wri...

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look at the pictures amd shoose the most typical prodiced sounds posmotrite na k

stepen okisleniya azota ne izmenyaestya pri perehode ot hno3 k 1 n2 3 kno2 2 no

v sheme prevrashenijs 2 x s0 x s4 x s

kovalentnaya polyarnaya svyaz imeet mesto v soedineniyah 1 serovodorod 2 ugarnyj

stepen okisleniya 4 v soedineniyah imeyut 1 kislorod 2 sera 3 azot 4 uglerod

odnu kovalentuyu svyaz imeet molekula 1 iodovoloroda 2 metana 3 azota 4 kisl

kovalentnaya polyarnaya svyaz v kazhdom iz dvuh veshestv 1 kcl naoh 2 hi h2o 3

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