найдите промежутки возрастания функции: [tex]f(x) = x ^{3} - 6x^{2} - 9[/tex]. Created by llasmos. algebra-ru

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July 2022 1 15 Report

найдите промежутки возрастания функции:
[tex]f(x) = x ^{3} - 6x^{2} - 9[/tex]

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Armenia2780 F(x)=x³-6x²-9;x€R

1)f'(x)=3x²-12x

2)3x²-12x>0
3)3x²-12x<0

3x(x-4)>0

__+___0__-____4__+__

x€(-oo;0)U(4;+oo) функция возрастает

x€(0;4) функция убывает

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