Решите уровнения
3(х+06)=3-х
[tex] \frac{5}{7} [/tex]х-[tex] \frac{3}{14} [/tex]х= -2
2(х+1.2)=2.7-х
[tex] \frac{7}{9} [/tex]х-[tex] \frac{5}{18} [/tex]х= -3
3(х+06)=3-х
[tex] \frac{5}{7} [/tex]х-[tex] \frac{3}{14} [/tex]х= -2
2(х+1.2)=2.7-х
[tex] \frac{7}{9} [/tex]х-[tex] \frac{5}{18} [/tex]х= -3
More Questions From This User See All
Answers & Comments
Verified answer