Решите СРОЧНО [tex] \sqrt{2x - 4} < 4[/tex][tex] \sqrt{5x + 1} \geqslant \sqrt{6x - 3 } [/tex]Найти сумму, разность и деление.1) z1=1+2i 2) z2=4-3i. Created by fil24218. algebra-ru

tex]Найти сумму, разность и деление.1) z1=1+2i 2) z2=4-3i...

$1)\; \; \; \; \sqrt{2x-4}$

$3)\; \; z_1=1+2i\; \; ,\; \; z_2=4-3i\\\\z_1+z_2=(1+2i)+(4-3i)=5-i\\\\z_1-z_2=(1+2i)-(4-3i)=-3+5i\\\\\frac{z_1}{z_2}=\frac{(1+2i)(4+3i)}{(4-3i)(4+3i)}=\frac{4+3i+8i+6i^2}{4^2-9i^2}=\frac{4+11i-6}{16+9}=\frac{-2+11i}{25}=-\frac{2}{25}+\frac{11}{25}\, i$

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