[tex] \sqrt{3x - 1} = 1 \\ \sqrt{6x + 4} = 2 \\ \sqrt{12 - x} = 6 \\ \sqrt{8x - 1 } = 1[/tex]
Нужно решить уравнение ​
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.

Answers & Comments


Copyright © 2025 SCHOLAR.TIPS - All rights reserved.