30 БАЛЛОВ.Помогите решить неравенство (9 класс):
[tex] | {x }^{2} - 12x + 25 | < 3x - 11[/tex]
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[tex] | {x }^{2} - 12x + 25 | < 3x - 11[/tex]
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|x² - 12x + 25| < 3x - 11[-x² + 12x - 25 < 3x - 11
[-x² + 12x - 25 < -3x + 11,
[-x² + 9x - 14 < 0
[-x² + 15x - 36 < 0,
[x² - 9x + 14 > 0
[x² - 15x + 36 > 0,
[(x - 2)(x - 7) > 0
[(x - 12)(x - 3) > 0,
[x ∈ (-∞; 2) ∪ (7; +∞)
[x ∈ (-∞; 3) ∪ (12; +∞)
3x - 11 > 0
x > 11/3
OTVET: x ∈ (7; +∞)