tex]решите неравенство ...

bkiskenov @bkiskenov

September 2021 1 5 Report

[tex] \frac{x + 2}{3 - x} > (0.5) {}^{ - 1} [/tex]
решите неравенство

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$\frac{x+2}{3-x}>(0,5)^{-1}\\\\\frac{x+2}{3-x}>(\frac{1}{2} )^{-1}\\\\\frac{x+2}{3-x}>2\\\\\frac{x+2}{3-x}-2>0\\\\\frac{x+2-6+2x}{3-x}>0\\\\\frac{3x-4}{3-x}>0\\\\\frac{3(x-1\frac{1}{3}) }{-(x-3)}>0\\\\\frac{x-1\frac{1}{3} }{x-3}$

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1 1/3 3

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Ответ : x ∈ (1 1/3 ; 3)

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