[tex]
\sqrt{(2x-4)^2}=6
\sqrt{x} -5/ \sqrt{x} +1= \sqrt{x} +4/ \sqrt{x} -8
[/tex]
Решите уравнения
\sqrt{(2x-4)^2}=6
\sqrt{x} -5/ \sqrt{x} +1= \sqrt{x} +4/ \sqrt{x} -8
[/tex]
Решите уравнения
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