√5 + √(x - 1) = 3
одз x ≥ 1
√(x - 1) = 3 - √5
x - 1 = (3 - √5)²
x = 1 + 9 - 6√5 + 5 = 15 - 6√5
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Verified answer
√5 + √(x - 1) = 3
одз x ≥ 1
√(x - 1) = 3 - √5
x - 1 = (3 - √5)²
x = 1 + 9 - 6√5 + 5 = 15 - 6√5