tex]СПАСИБО БОЛЬШОЕ!!!...

May 2022 1 12 Report

Помогите решить уравнение пожалуйста!!!
1.
[tex] \frac{30}{x + 1} + \frac{30}{x - 1} = 3 \frac{1}{6} [/tex]
2.
[tex] \frac{350}{x} - \frac{350}{x - 20} = 2[/tex]
СПАСИБО БОЛЬШОЕ!!!

Answers & Comments

maymr

$\frac{30}{x+1}+\frac{30}{x-1}-\frac{19}{6}=0\\\\\frac{180(x-1)+180(x+1)-19(x+1)(x-1)}{6(x+1)(x-1)}=0\\\\\frac{-19x^2+360x+19}{6(x+1)(x-1)}=0\\\\OD3:x\neq-1\ and\ x\neq1\\\\19x^2-360x-19=0\\D=(-360)^2-4*19*(-19)=131044\\\sqrt{131044}=362\\\\x_1=\frac{360-362}{19*2}=-\frac{1}{19}\\\\x_2=\frac{360+362}{19*2}=19$

Ответ: -1/19; 19

$\frac{350}{x}-\frac{350}{x-20}-2=0\\\\\frac{350(x-20)-350x-2x(x-20)}{x(x-20)}=0\\\\\frac{-2x^2+40x-7000}{x(x-20)}=0\\\\OD3:x\neq0\ and\ x\neq20\\\\2x^2-40x+7000=0\\D=(-40)^2-4*2*7000=-54400$

Ответ: нет решения.

2 votes Thanks 2

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