Решите пределы
[tex]lim \frac{6x + 4}{ \sin(x) } [/tex]
[tex]lim \frac{ {x}^{2} }{5 { \cos}^{2}4x - 5} [/tex]
в обоих х->0
[tex]lim \frac{6x + 4}{ \sin(x) } [/tex]
[tex]lim \frac{ {x}^{2} }{5 { \cos}^{2}4x - 5} [/tex]
в обоих х->0
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Answers & Comments
lim((6x+4)/sinx)=lim(4/0)=∞ <sin0=0>
lim(x²/(5cos²4x-5))=<0/0>=lim((x²/(5(1-sin²4x-1))=lim((x²/(-5sin²4x))=lim (1/4*4x²)/(-5sin²4x)=-1/4:5=-1/20=-0.05 1замечательный предел