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лерочка1312
@лерочка1312
July 2022
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[tex]| \frac{x-5}{x} |[/tex]×(x²-x-12)≤0
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sedinalana
Verified answer
|(x-5)/x|≥0 при любом х,кроме х=0⇒
x²-x-12≤0
x1+x2=1 U x1*x2=-12⇒x1=-3 U x2=4
-3≤x≤4 U x≠0
x∈[-3;0) U (0;4]
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лерочка1312
почему 0 если х не = 0
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Answers & Comments
Verified answer
|(x-5)/x|≥0 при любом х,кроме х=0⇒x²-x-12≤0
x1+x2=1 U x1*x2=-12⇒x1=-3 U x2=4
-3≤x≤4 U x≠0
x∈[-3;0) U (0;4]