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nikitos200074
@nikitos200074
August 2022
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1)x^7+5=0
2)x^4-16=0
3)[tex] \sqrt[3]{4x+2} [/tex]=-4
4)[tex] \sqrt{4x+1} [/tex] =-4
5)[tex] \sqrt{17+2x-3x^2} [/tex]=x+1
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dmitrija753
1)x^7=-5
x=7√-5
2)x^4=4+16
x^4=20
x=4√20
x=4-√20
3)
3x+8=-16
3x=-16-8
3x=-24
x=-8
4)4x=-4-1
4x=-5
x=-5/4
5)16+x-3x²=0
3x²-x-16=0
x1=1+√193/6
x2= 1-1√193/6
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nikitos200074
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Answers & Comments
x=7√-5
2)x^4=4+16
x^4=20
x=4√20
x=4-√20
3)
3x+8=-16
3x=-16-8
3x=-24
x=-8
4)4x=-4-1
4x=-5
x=-5/4
5)16+x-3x²=0
3x²-x-16=0
x1=1+√193/6
x2= 1-1√193/6