Знайти f(x), якщо
[tex]f( \frac{y}{x} ) = \frac{ \sqrt{ {x}^{2} + {y}^{2}} }{x} [/tex]
(x>0).
[tex]f( \frac{y}{x} ) = \frac{ \sqrt{ {x}^{2} + {y}^{2}} }{x} [/tex]
(x>0).
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на фото..............