tex]xy³)⁴...

DashaNya1312 @DashaNya1312

July 2022 1 3 Report

упростите
[tex]2 \frac{2}{3}[/tex]x²y⁸([tex]-1 \frac{1}{2} [/tex]xy³)⁴

Answers & Comments

Rossomaxa2001 $2 \frac{2}{3} x^{2}y ^{3}*(-1 \frac{1}{2}xy ^{3}) ^{4}=2 \frac{2}{3} x^{2}y ^{3}*(- \frac{3}{2}xy ^{3}) ^{4}= \frac{8}{3} x^{2}y ^{3}* \frac{81}{16} x^{4}y ^{12}= \frac{27}{2} x^{2+4}$ $y^{3+12}= \frac{27}{2} x^{6}y ^{15}=13 \frac{1}{2} x^{6}y ^{15}$

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