Ответ:
tg²150°-cos120°+cos180°= tg²(180°-150°)- cos(180°-120°)+(-1)= tg²30°-cos60°-1= (√3/3)²-1/2-1=6/18-9/18-18/18= -21/18
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Ответ:
tg²150°-cos120°+cos180°= tg²(180°-150°)- cos(180°-120°)+(-1)= tg²30°-cos60°-1= (√3/3)²-1/2-1=6/18-9/18-18/18= -21/18