Home
О нас
Products
Services
Регистрация
Войти
Поиск
АлишерТопОне
@АлишерТопОне
July 2022
1
1
Report
Tg20+4sin20=корень из 3
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
oganesbagoyan
Verified answer
tq20° + 4sin20°
=(sin20° + 4sin20°cos20°) /cos20° =
(sin20° +2sin40°) /cos20° = (sin40° +sin20°+sin40°) /cos20
° =
(2sin30°cos10° +sin40°) /cos20° =(cos10° +sin40°) /cos20
° =
=(cos10° +cos50°) /cos20° = 2cos30°cos20° /cos20° =2cos30° =2*(√3)/2
=
√3.
* * * * * * * исполльзованы тригонометрические формулы
* * * * * * *
tqα =sinα /cos
α ;
2sinα*cosα =sin2α; sinα+sinβ =2sin(α+ β)/2 * cos(α- β)/2 ; sinα =cos(90° -
α) и
cosα+cosβ =2cos(α+ β)/2 * cos(α-
β)/2.
---------------
Удачи !
16 votes
Thanks 33
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Tg20+4sin20=корень из 3..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
tq20° + 4sin20° =(sin20° + 4sin20°cos20°) /cos20° =(sin20° +2sin40°) /cos20° = (sin40° +sin20°+sin40°) /cos20° =
(2sin30°cos10° +sin40°) /cos20° =(cos10° +sin40°) /cos20° =
=(cos10° +cos50°) /cos20° = 2cos30°cos20° /cos20° =2cos30° =2*(√3)/2 = √3.
* * * * * * * исполльзованы тригонометрические формулы * * * * * * *
tqα =sinα /cosα ;2sinα*cosα =sin2α; sinα+sinβ =2sin(α+ β)/2 * cos(α- β)/2 ; sinα =cos(90° - α) и cosα+cosβ =2cos(α+ β)/2 * cos(α- β)/2.
---------------
Удачи !