Home
О нас
Products
Services
Регистрация
Войти
Поиск
Milansss
@Milansss
August 2022
1
8
Report
tg^2a cos^2a+ctg^2asin2a
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
DAD2281
Скобки, наверное, так
(tg^2a-sin^2a) / (ctg^2a-cos^2a)
Преобразуем
{sin(a)^2[1-cos(a)^2]/ cos(a)^2* }//
{cos(a)^2[1-sin(a)^2] /sin(a)^2}=
Sin(a)^6/cos(a)^6=tg(a)^6;
Ответ tg(a)^6;Скобки, наверное, так
(tg^2a-sin^2a) / (ctg^2a-cos^2a)
Преобразуем
{sin(a)^2[1-cos(a)^2]/ cos(a)^2* }//
{cos(a)^2[1-sin(a)^2] /sin(a)^2}=
Sin(a)^6/cos(a)^6=tg(a)^6;
Ответ tg(a)^6;
1 votes
Thanks 1
More Questions From This User
See All
Milansss
August 2022 | 0 Ответы
pomogite pliiiz 31 ball
Answer
Milansss
July 2022 | 0 Ответы
nefteprodukty krome benzinaligroinakerosinagazojl i mazuta
Answer
Milansss
October 2021 | 0 Ответы
sayahatka shygu esse 50 ball
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "tg^2a cos^2a+ctg^2asin2a..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
(tg^2a-sin^2a) / (ctg^2a-cos^2a)
Преобразуем
{sin(a)^2[1-cos(a)^2]/ cos(a)^2* }//
{cos(a)^2[1-sin(a)^2] /sin(a)^2}=
Sin(a)^6/cos(a)^6=tg(a)^6;
Ответ tg(a)^6;Скобки, наверное, так
(tg^2a-sin^2a) / (ctg^2a-cos^2a)
Преобразуем
{sin(a)^2[1-cos(a)^2]/ cos(a)^2* }//
{cos(a)^2[1-sin(a)^2] /sin(a)^2}=
Sin(a)^6/cos(a)^6=tg(a)^6;
Ответ tg(a)^6;