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Milansss
@Milansss
August 2022
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tg^2a cos^2a+ctg^2asin2a
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DAD2281
Скобки, наверное, так
(tg^2a-sin^2a) / (ctg^2a-cos^2a)
Преобразуем
{sin(a)^2[1-cos(a)^2]/ cos(a)^2* }//
{cos(a)^2[1-sin(a)^2] /sin(a)^2}=
Sin(a)^6/cos(a)^6=tg(a)^6;
Ответ tg(a)^6;Скобки, наверное, так
(tg^2a-sin^2a) / (ctg^2a-cos^2a)
Преобразуем
{sin(a)^2[1-cos(a)^2]/ cos(a)^2* }//
{cos(a)^2[1-sin(a)^2] /sin(a)^2}=
Sin(a)^6/cos(a)^6=tg(a)^6;
Ответ tg(a)^6;
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Answers & Comments
(tg^2a-sin^2a) / (ctg^2a-cos^2a)
Преобразуем
{sin(a)^2[1-cos(a)^2]/ cos(a)^2* }//
{cos(a)^2[1-sin(a)^2] /sin(a)^2}=
Sin(a)^6/cos(a)^6=tg(a)^6;
Ответ tg(a)^6;Скобки, наверное, так
(tg^2a-sin^2a) / (ctg^2a-cos^2a)
Преобразуем
{sin(a)^2[1-cos(a)^2]/ cos(a)^2* }//
{cos(a)^2[1-sin(a)^2] /sin(a)^2}=
Sin(a)^6/cos(a)^6=tg(a)^6;
Ответ tg(a)^6;