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Marishka97
@Marishka97
July 2022
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докажите, что при всех допустимых значениях a верно равенство:
(1-sin^2a)/(1-cos^2a)=1/tg^2a
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mmb1
Verified answer
(1-sin^2a)/(1-cos^2a)=1/tg^2a
из формулы sin^2+cos^2=1
(1-sin^2a)=cos^2a
1-cos^2a=sin^2a
cos^2a/sin^2a=ctg^2a=1/tg^2a
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Answers & Comments
Verified answer
(1-sin^2a)/(1-cos^2a)=1/tg^2aиз формулы sin^2+cos^2=1
(1-sin^2a)=cos^2a
1-cos^2a=sin^2a
cos^2a/sin^2a=ctg^2a=1/tg^2a