Home
О нас
Products
Services
Регистрация
Войти
Поиск
bika2016p2z0ub
@bika2016p2z0ub
July 2022
1
7
Report
tg^2a+ctg^2a-6/tg^2a+ctg^2a+2
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
Tg^2a+ctg^2a-6=sin²a/cos²a+cos²a/sin²a -6=
=(1-cos2a)/(1+cos2a) +(1+cos2a)/(1-cos2a) - 6=
=(1-2cos2a+cos²2a+1+2cos2a+cos²2a -6+6cos²2a)/(1-cos²2a)=
=(8cos²2a-4)/(1-cos²2a)=4(2cos²2a-1)/sin²2a=4cos4a/sin²2a
Tg^2a+ctg^2a + 2=sin²a/cos²a+cos²a/sin²a +2=
=(1-cos2a)/(1+cos2a) +(1+cos2a)/(1-cos2a) + 2=
=(1-2cos2a+cos²2a+1+2cos2a+cos²2a + 2- 2cos²2a)/(1-cos²2a)=
=4/(1-cos²2a)=4/sin²2a
(Tg^2a+ctg^2a - 6)/(Tg^2a+ctg^2a + 2)=4cos4a/sin²a:4/sin²a=
=4cos4a/sin²2a * sin²2a/4=cos4a
0 votes
Thanks 0
More Questions From This User
See All
bika2016p2z0ub
July 2022 | 0 Ответы
tg^2a+ctg^2a+2...
Answer
bika2016p2z0ub
July 2022 | 0 Ответы
tg^2a+ctg^2a+2...
Answer
bika2016p2z0ub
June 2021 | 0 Ответы
fenol ne vstupaet v reakciyu s veshestvom formula kotorogo hno3 h2o k naoh
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "tg^2a+ctg^2a+2 ..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
=(1-cos2a)/(1+cos2a) +(1+cos2a)/(1-cos2a) - 6=
=(1-2cos2a+cos²2a+1+2cos2a+cos²2a -6+6cos²2a)/(1-cos²2a)=
=(8cos²2a-4)/(1-cos²2a)=4(2cos²2a-1)/sin²2a=4cos4a/sin²2a
Tg^2a+ctg^2a + 2=sin²a/cos²a+cos²a/sin²a +2=
=(1-cos2a)/(1+cos2a) +(1+cos2a)/(1-cos2a) + 2=
=(1-2cos2a+cos²2a+1+2cos2a+cos²2a + 2- 2cos²2a)/(1-cos²2a)=
=4/(1-cos²2a)=4/sin²2a
(Tg^2a+ctg^2a - 6)/(Tg^2a+ctg^2a + 2)=4cos4a/sin²a:4/sin²a=
=4cos4a/sin²2a * sin²2a/4=cos4a