Очень нужна помощь! ((tg2xtgx)/(tg2x-tgx))-2sin(45+x)sin(45-x)=0 (там 45 градусов). Created by 311KKK. matematika-ru

(tg2x-tgx))-2sin(45+x)sin(45-x)=0 (там 45 градусов)...

August 2022 1 3 Report

Очень нужна помощь!
((tg2xtgx)/(tg2x-tgx))-2sin(45+x)sin(45-x)=0
(там 45 градусов)

Answers & Comments

angel200022 Я не знаю может быть
2sin^2x+3cosx=02(1-cos^2x)+3cosx=02-2cos^2x-3cosx=02cos^2x-3cosx-2=0cosx=a2a^2-3a-2=0d=9+16=25=5^2a=1 a=-1/2cosx=1x=2Pikcosx=-1/2x=+-Pi/3+Pik; k ∈z

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311KKK спасибо все равно!

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