The blade of a table saw has a diameter of 25.4 cm and rotates with a frequency of 750. What is the magnitude of the centripetal acceleration at the edge of the blade?
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Дано:
D = 25,4 см = 0,254 м
R = D/2 = 0,127 м
ω = 750 рад/с
___________
aₙ - ?
Центростремительное ускорение
aₙ = ω²·R
aₙ = 750² · 0,127 ≈ 71 400 м/с²
Given:
D = 25.4 cm = 0.254 m
R = D / 2 = 0.127 m
ω = 750 rad / s
___________
aₙ -?
Centripetal acceleration
aₙ = ω² · R
aₙ = 750² · 0.127 ≈ 71,400 m / s²