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saldyrovaa
@saldyrovaa
July 2022
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Точка В(к, -1) лежит на графике уравнения 5xy-4y^2=3y-4x-6. Найдите к?
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rubilovalex
Подставляем координаты точки в уравнение: 5*k*(-1)-4*(-1)^2=3*(-1)-4*k-6; -5k-4= -3-4k-6; -5k+4k= -9+4; -к= -5; k=(-5)/(-1)=5. Ответ: k=5.
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