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Lolllo123
@Lolllo123
November 2021
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Только 1 и 2 умоляю я в школе
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Trofimkirillov
Вариант 1.
N°1
а)(a+3)²=a²+2*a*3+3²=a²+6a+9
б)(a-2)(a+2)=(a)²-2²=a²-4
в)(x+3)(x²-3x+9)=(x)³+3³=x³+27
г)(3a+2)(2-3a)=(2+3a)(2-3a)=2²-(3a)²=4-9a²
д)(c²-4)²=(c²)²-2*c²*4+4²=c⁴-8c²+16
е)(x-2)(x+1)=x²+x-2x-2=x²-x-2
N°2
а)5a+5b=5(a+b)
б)y²-16x²=(y)²-(4x)²=(y-4x)(y+4x)
в)a²+6a+9=(a)²+2*a*3+3²=(a+3)²
г)6(x-y)+a(y-x)=6(x-y)-a(x-y)=(6-a)(x-y)
д)ax-3x-4a+12=ax-4a-3x+12=(ax-4a)-(3x-12)=a(x-4)-3(x-4)=(a-3)(x-4)
Вариант 2.
N°1
а)(a-2)²=(a)²-2*a*2+2²=a²-4a+4
б)(a-3)(a+3)=(a)²-3²=a²-9
в)(x-1)(x²+x+1)=(x)³-1³=x³-1
г)2(c-2)(2+c)=2(c-2)(c+2)=2(c²-4)=2c²-8
д)(x²+3)²=(x²)²+2*x²*3+3²=x⁴+6x²+9
е)(a-3)(a+6)=a²+6a-3a-18=a²+3a-18
N°2
а)3x-3y=3(x-y)
б)a²-9b²=(a)²-(3b)²=(a-3b)(a+3b)
в)a²+4a+4=(a)²+2*a*2+2²=(a+2)²
г)a(b-c)+3(c-b)=a(b-c)-3(b-c)=(a-3)(b-c)
д)3a+3-na-n=3a-na+3-n=(3a-na)+(3-n)=a(3-n)+(3-n)=(a+1)(3-n)
2 votes
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Answers & Comments
N°1
а)(a+3)²=a²+2*a*3+3²=a²+6a+9
б)(a-2)(a+2)=(a)²-2²=a²-4
в)(x+3)(x²-3x+9)=(x)³+3³=x³+27
г)(3a+2)(2-3a)=(2+3a)(2-3a)=2²-(3a)²=4-9a²
д)(c²-4)²=(c²)²-2*c²*4+4²=c⁴-8c²+16
е)(x-2)(x+1)=x²+x-2x-2=x²-x-2
N°2
а)5a+5b=5(a+b)
б)y²-16x²=(y)²-(4x)²=(y-4x)(y+4x)
в)a²+6a+9=(a)²+2*a*3+3²=(a+3)²
г)6(x-y)+a(y-x)=6(x-y)-a(x-y)=(6-a)(x-y)
д)ax-3x-4a+12=ax-4a-3x+12=(ax-4a)-(3x-12)=a(x-4)-3(x-4)=(a-3)(x-4)
Вариант 2.
N°1
а)(a-2)²=(a)²-2*a*2+2²=a²-4a+4
б)(a-3)(a+3)=(a)²-3²=a²-9
в)(x-1)(x²+x+1)=(x)³-1³=x³-1
г)2(c-2)(2+c)=2(c-2)(c+2)=2(c²-4)=2c²-8
д)(x²+3)²=(x²)²+2*x²*3+3²=x⁴+6x²+9
е)(a-3)(a+6)=a²+6a-3a-18=a²+3a-18
N°2
а)3x-3y=3(x-y)
б)a²-9b²=(a)²-(3b)²=(a-3b)(a+3b)
в)a²+4a+4=(a)²+2*a*2+2²=(a+2)²
г)a(b-c)+3(c-b)=a(b-c)-3(b-c)=(a-3)(b-c)
д)3a+3-na-n=3a-na+3-n=(3a-na)+(3-n)=a(3-n)+(3-n)=(a+1)(3-n)