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Wolf15051
@Wolf15051
December 2021
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гюйс
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B(n)=b1 * q^(n-1)
b(5)=b1 * q^(5-1)=b1*q^4
b1=2√3
q=√3
b(5)=2√3 * (√3)^4=2√3 * 3²=18√3
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Answers & Comments
Verified answer
B(n)=b1 * q^(n-1)b(5)=b1 * q^(5-1)=b1*q^4
b1=2√3
q=√3
b(5)=2√3 * (√3)^4=2√3 * 3²=18√3