ТРЕТЬЕ ЗАДАНИЕ С РЕШЕНИЕМ. Created by lolllpop. algebra-ru

ТРЕТЬЕ ЗАДАНИЕ С РЕШЕНИЕМ...

sedinalana A2=23,a4=20
d=(a4-a2)/2=(20-23)/2=-1,5
a1=a2-d=23+1,5=24,5
S12=(2a1+11d)*12/2
S12=(49-16,5)*6=32,5*6=195

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ПрофиЗнания N3

S12 - ?
a2=23
a4=20

a1+d=23
a1+3d=20 Отнимаем

3d-d=20-23
2d=-3
d=-1,5
a1=23-d=23+1,5=24,5

S12=2a1+11d/2 * 12 = (2a1+11d)*6=(49-16,5)*6=32,5*6=195

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