Home
О нас
Products
Services
Регистрация
Войти
Поиск
OLeG1337KuLL
@OLeG1337KuLL
July 2022
1
1
Report
Тригонометрические функции числового аргумента вариант 2 (только 1,2,3,6,8,9)
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
Verified answer
1
sina=12/13
cosa=-√(1-sin²a)=-√(1-144/169)=-√)25/169)=-5/13
tga=sina/cosa=12/13:(-5/13)=-12/13*13/5=-12/5
ctga=1/tga=1:(-12/5)=-5/12
2
cos9π/4=cos(2π+π/4)=cosπ/4=√2/2
3
tg²a*(1+cos2a)-sin²a=sin²a/cos²a*2cos²a-sin²a=2sin²a-sin²a=sin²a
6
cos²π/12-sin²π/12=cos(2*π/12)=cosπ/6=√3/2
8
1-sin2a=sin²a+cos²a-2sinacosa-(sina-cosa)²
9
(1-sin2a)/(ctga*tga-25sinacosa)=(1-sin2a)/(1-sin2a)=1
2 votes
Thanks 0
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Тригонометрические функции числового аргумента вариант 2 (только 1,2,3,6,8,9)..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
1sina=12/13
cosa=-√(1-sin²a)=-√(1-144/169)=-√)25/169)=-5/13
tga=sina/cosa=12/13:(-5/13)=-12/13*13/5=-12/5
ctga=1/tga=1:(-12/5)=-5/12
2
cos9π/4=cos(2π+π/4)=cosπ/4=√2/2
3
tg²a*(1+cos2a)-sin²a=sin²a/cos²a*2cos²a-sin²a=2sin²a-sin²a=sin²a
6
cos²π/12-sin²π/12=cos(2*π/12)=cosπ/6=√3/2
8
1-sin2a=sin²a+cos²a-2sinacosa-(sina-cosa)²
9
(1-sin2a)/(ctga*tga-25sinacosa)=(1-sin2a)/(1-sin2a)=1