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weveron
@weveron
August 2022
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Тригонометрия, помогите пожалуйста!
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sedinalana
Verified answer
11
(cos²2a-sin²2a)(cos²2a+sin²2a)/(cos²2a-sin²2a) -(cos²2a-2cos2a*sin2a+sin²2a)=
=1-(1-sin4a)=1-1+sin4a=sin4a
12
(1-sin²a)(1+sin²a)/sin²a(1+sin²a)=cos²a/sin²a=tg²a
13
1)1/(1-tgx)-1/(1+tgx)=(1+tgx-1+tgx)/(1-tg²x)=2tgx/(1-tg²x)=tg2x
2)cos²x-sin²x=cos2x
3)tg2x*cos2x=sin2x/cos2x*cos2x=sin2x
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Verified answer
11(cos²2a-sin²2a)(cos²2a+sin²2a)/(cos²2a-sin²2a) -(cos²2a-2cos2a*sin2a+sin²2a)=
=1-(1-sin4a)=1-1+sin4a=sin4a
12
(1-sin²a)(1+sin²a)/sin²a(1+sin²a)=cos²a/sin²a=tg²a
13
1)1/(1-tgx)-1/(1+tgx)=(1+tgx-1+tgx)/(1-tg²x)=2tgx/(1-tg²x)=tg2x
2)cos²x-sin²x=cos2x
3)tg2x*cos2x=sin2x/cos2x*cos2x=sin2x