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sasha514406
@sasha514406
July 2022
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Тригонометрия, уравнения
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sharadi
Verified answer
1) Cosα= -3/5, α∈IIIчетв.
Нaйти Sinα и tgα
решение:
Sin²α + Cos²α = 1
Sin²α = 1 - Cos²α = 1 - 9/25 = 16/25
Sinα = -4/5
tgα = -4/5: (-3/5) = 4/3
2) Sin(π-α) = Sinα
Cos²(π +α) = Cos²α
Cos(3π/2 - α) = -Sinα
наш пример:
Sinα + Cos²α/Sinα = (Sin²α + Cos²α)/Sinα = 1/Sinα
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Thanks 1
sharadi
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Answers & Comments
Verified answer
1) Cosα= -3/5, α∈IIIчетв.Нaйти Sinα и tgα
решение:
Sin²α + Cos²α = 1
Sin²α = 1 - Cos²α = 1 - 9/25 = 16/25
Sinα = -4/5
tgα = -4/5: (-3/5) = 4/3
2) Sin(π-α) = Sinα
Cos²(π +α) = Cos²α
Cos(3π/2 - α) = -Sinα
наш пример:
Sinα + Cos²α/Sinα = (Sin²α + Cos²α)/Sinα = 1/Sinα