Х + y = 6
X = 6 - y
X^2 = ( 6 - y)^2 = 36 - 12y + y^2
y^2 - 2x^2 = 8
y^2 -2( 36 - 12y + y^2 ) = 8
y^2 - 72 + 24y - 2y^2 = 8
- y^2 + 24y - 80 = 0
D = 576 - 320 = 256 = 16^2
y1 = ( - 24 + 16 ) : ( - 2 ) = 4
y2 = ( - 24 - 16 ) : ( - 2 ) = 20
X = 6 - y
X1 = 6 - 4 = 2
X2 = 6 - 20 = - 14
Ответ ( 2 ; 4 ) ; ( - 14 ; 20 )
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Verified answer
Система уравнений{у²-2х²=8
{х+у=6
{y²-2x²=8
{y= 6-x
Метод подстановки
(6-х)² -2х²=8
6² -2*6*х +х² - 2х² =8
36 -12х -х²- 8=0
-x²-12x + 28=0 |*(-1)
x² +12x -28=0
D= 12² -4*1*(-28) = 144+112=256= 16²
x₁= (-12+16)/ (2*1) = 4/2 = 2
x₂= (- 12-16)/2 = -28/2 = -14
y₁= 6-2=4
y₂= 6-(-14) = 6+14=20
ответ: (2 ;4) , (-14;20).