(у-35)+12=32 56-(+12)=24 55-(х-15)=3 решите 2 спосабами пожалуста !!СРОЧНО НАДО!!!
(у-35)+12=32
y-35=32-12
y-35=20
y=35+20
y= 55
(y-35)+12=32
y-35+12-32=0
y- 55=0
y=55
=====================================
55-(x-15)=3
-(x-15)=3-55
-x+15=-52
-x=-52-15
-x= -76
x=67
55-x+15-3=0
-x+67 =0
-x=-67
==================================
во втором проверь условие
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(у-35)+12=32
y-35=32-12
y-35=20
y=35+20
y= 55
(y-35)+12=32
y-35+12-32=0
y- 55=0
y=55
=====================================
55-(x-15)=3
-(x-15)=3-55
-x+15=-52
-x=-52-15
-x= -76
x=67
55-(x-15)=3
55-x+15-3=0
-x+67 =0
-x=-67
x=67
==================================
во втором проверь условие