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Объяснение:

[tex]\left \{ {{u-5t=5} \atop {5u+2t=26}} \right. |^{-5} _{1}\\\\\left \{ {{-5u+25t=-25} \atop {5u+2t=26}} \right. |+\\\\27t=1\\t=\frac{1}{27} \\\\u-5*\frac{1}{27} =5\\\\u=5+\frac{5}{27} \\\\u=\frac{140}{27} \\\\u=5\frac{5}{27}[/tex]