CnH2n+1NH2 + HBr = CnH2n+1NH3Br
n(CnH2n+1NH2) = 0.56 : 22.4 = 0.025
n(CnH2n+1NH2) = n(CnH2n+1NH3Br) = 0.025
M(CnH2n+1NH3Br) = 3.5 : 0.025 = 140
12n+2n+1+14+3+80 = 140
14n = 42
n = 3
Ответ: C3H9N
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CnH2n+1NH2 + HBr = CnH2n+1NH3Br
n(CnH2n+1NH2) = 0.56 : 22.4 = 0.025
n(CnH2n+1NH2) = n(CnH2n+1NH3Br) = 0.025
M(CnH2n+1NH3Br) = 3.5 : 0.025 = 140
12n+2n+1+14+3+80 = 140
14n = 42
n = 3
Ответ: C3H9N