Ответ:
дано
m(AL) = 3.24 g
-----------------
m(Al2(SO4)3) - ?
2Al+3H2SO4-->Al2(SO4)3+3H2
M(Al) =27 g/mol
n(Al) = m/M = 3.24 / 27 = 0.12 mol
2n(AL) = n(Al2(SO4)3
n(Al2(SO4)3) = 0.12 / 2 = 0.6 mol
M(Al2(SO4)3) = 342 g/mol
m(Al2(SO4)3) = n*M = 0.6 * 342 = 205,2 g
ответ: 205.2 г
Объяснение:
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Answers & Comments
Ответ:
дано
m(AL) = 3.24 g
-----------------
m(Al2(SO4)3) - ?
2Al+3H2SO4-->Al2(SO4)3+3H2
M(Al) =27 g/mol
n(Al) = m/M = 3.24 / 27 = 0.12 mol
2n(AL) = n(Al2(SO4)3
n(Al2(SO4)3) = 0.12 / 2 = 0.6 mol
M(Al2(SO4)3) = 342 g/mol
m(Al2(SO4)3) = n*M = 0.6 * 342 = 205,2 g
ответ: 205.2 г
Объяснение: