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masyanyako
@masyanyako
April 2021
1
6
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У треугольника ABC стороны AB и BC равны.Сторона AC равна 15см.Периметр треугольника равен 65см.Какова длина стороныAB?
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Настюха228Крут
1)Р=АВ+ВС+АС
65=х+х+15
2х=65-15
2х=50 (:2
х=25 см
АВ=25см
2 votes
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Answers & Comments
65=х+х+15
2х=65-15
2х=50 (:2
х=25 см
АВ=25см