Ответ:
[tex]40 + 200 = 240 \\ \frac{1}{r} = \frac{1}{240} + \frac{1}{120} = \frac{1 + 2}{240} = \frac{3}{240 =} = \frac{1}{80} \\ r = 80 \\ 80 + 60 = 140om \\ 30 \div 140 = 0.21a[/tex]
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Ответ:
[tex]40 + 200 = 240 \\ \frac{1}{r} = \frac{1}{240} + \frac{1}{120} = \frac{1 + 2}{240} = \frac{3}{240 =} = \frac{1}{80} \\ r = 80 \\ 80 + 60 = 140om \\ 30 \div 140 = 0.21a[/tex]