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lumekelluke
@lumekelluke
September 2021
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Угол параллелограмма 30 С и высота равна 4 дм, найдите площадь параллелограмма, если высота проведенная из вершины тупого угла делит соответcтвующее основание пополам.
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sedinalana
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ABCD/BH_|_AD,AH=HD,BH=4дм,<A=30⇒BH=1/2*AB⇒AB=8дм
AH=√(AB²-BH²)=√(64-16)=√48=4√3
AD=2*4√3=8√3дм
S=AD*BH=8√3*4=32√3дм²
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Verified answer
ABCD/BH_|_AD,AH=HD,BH=4дм,<A=30⇒BH=1/2*AB⇒AB=8дмAH=√(AB²-BH²)=√(64-16)=√48=4√3
AD=2*4√3=8√3дм
S=AD*BH=8√3*4=32√3дм²