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Paraskevova
@Paraskevova
July 2022
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Укажите число атомов в 4 г калиция Ca.
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chernovakatya
N(Ca) = 4г/40гмоль = 0,1 моль.
N(Ca) = 6,02*10(23 степени) * 0,1 моль = 0,602*10(23 степени)
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Answers & Comments
N(Ca) = 6,02*10(23 степени) * 0,1 моль = 0,602*10(23 степени)