х²-х-6=0
а=1, в=-1, с=-6
D=в²-4ас=(-1)²-4×1×(-6)=25
х₁,₂=(-в±√D)/2a
х₁=(1-5)/2=-2
х₂=(1+5)/2=3
Ответ: -2
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х²-х-6=0
а=1, в=-1, с=-6
D=в²-4ас=(-1)²-4×1×(-6)=25
х₁,₂=(-в±√D)/2a
х₁=(1-5)/2=-2
х₂=(1+5)/2=3
Ответ: -2